• 保证行不变，枚举列
• 保证列不变，枚举行
• 遇到自身则跳过

代码如下：

#include <iostream>
using namespace std;
typedef long long LL;
const char nl = '\n';
const int N = 2e5 + 10;
void solve()
{
    string s;
    cin >> s;
    for (int i = 0; i < 8; ++i)
    {
        if ((char)('a' + i) != s[0])
            cout << (char)('a' + i) << s[1] << nl;
        if ((i + 1) != s[1] - '0')
            cout << s[0] << i + 1 << nl;
    }
}
int main()
{
    int t;
    cin >> t;
    while (t--)
    {
        solve();
    }
    return 0;
}

```[题解.md][1]


  [1]: https://www.lxxblog.cfd/usr/uploads/2024/11/1958569463.md